• Here is problem 17 from 1.2. Let X2n be the group whose presentation is displayed in (1.2), i.e., <x,y|xn = y2 = 1, x y = y x2>.
  • (a) Show that if n = 3k, then X2n has order 6, and it has the same generators and relations as D6 when x is replaced by r and y by s.
  • (b) Show that if (3,n)=1, then x satisfies the additional relation: x=1. In this case deduce that X2n has order 2. [Use the facts that xn = 1 and x3 = 1.]
  • Here is problem 18 from 1.2. Let Y be the group whose presentation is displayed in (1.3), i.e., Y = <u,v|u4 = v3 = 1, u v = v2 u2>.
  • (a) Show that v2 = v-1. [Use the relation v3 = 1.]
  • (b) Show that v commutes with u3. [Show that v2 u3 v = u3 by writing the left hand side as (v2 u2)(u v) and using the relations to reduce this to the right hand side. Then use part (a).]
  • (c) Show that v commutes with u. Show that u9 = u and then use part (b).]
  • (d) Show that u v = 1. [Use part (c) and the last relation.]
  • (e) Show that u = 1, deduce that v = 1, and conclude that Y = 1. [Use part (d) and the equation u4 v3 = 1.]